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4x^2+144x+112=0
a = 4; b = 144; c = +112;
Δ = b2-4ac
Δ = 1442-4·4·112
Δ = 18944
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{18944}=\sqrt{256*74}=\sqrt{256}*\sqrt{74}=16\sqrt{74}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(144)-16\sqrt{74}}{2*4}=\frac{-144-16\sqrt{74}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(144)+16\sqrt{74}}{2*4}=\frac{-144+16\sqrt{74}}{8} $
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